3x^2=35x+12

Solution for 3x^2=35x+12 equation:

3x^2=35x+12

We move all terms to the left:

3x^2-(35x+12)=0

We get rid of parentheses

3x^2-35x-12=0

a = 3; b = -35; c = -12;
Δ = b2-4ac
Δ = -352-4·3·(-12)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-37}{2*3}=\frac{-2}{6}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+37}{2*3}=\frac{72}{6}
=12
$